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Easycafe Crack Serial 36


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The identity element of a matrix subgroup is the identity of the group

Let $G$ be a group, and $M$ a non-zero matrix from some field $F$ which forms a subgroup of $GL(n,F)$.
I read in the book of Matsumoto that the group $M \cong G$ if and only if $1 \in M$ is the only element in $G$ which is an eigenvector of every element of $M$.
How can I prove this?
I saw this question, but I do not really know how to use the relations given
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